Question

How do you simplify `sqrt(121x^10)`?

Answer 1

`sqrt(121x^10) = 11abs(x)^5`

Explanation:

If `a >= 0` then `sqrt(a^2) = a`

For any `a in RR`, `(-a)^2 = a^2`

Hence: `sqrt(a^2) = abs(a)` for all `a in RR`

So:

`sqrt(121x^10) = sqrt((11x^5)^2) = abs(11x^5) = 11abs(x)^5`