# How do you simplify sqrt(125j^12)?

Jan 26, 2017

$= 5 {j}^{6} \sqrt{5}$

#### Explanation:

It is helpful when finding roots, to write the number under the root as the product of its prime factors.

sqrt(125j^12) = sqrt(5xx5xx5xx j^12

$= \sqrt{5 \times {5}^{2} {j}^{12}}$

Find the roots where possible:

$= 5 {j}^{6} \sqrt{5}$

(For indices- divide the index by the root)