Question

How do you simplify `\sqrt { 128r ^ { 3} }`?

Answer 1

`8rsqrt(2r)`

Explanation:

Using that

`sqrt(ab)=sqrt(a)sqrt(b)` for `a,b>=0`
we write

#sqrt(128r^3)=sqrt(64r^2*2*r)=8r*sqrt(2r) #