How do you simplify #sqrt(16b)^4#?
1 Answer
Apr 7, 2015
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#sqrt(16*b^4)# =#+-4b^2# -
We use the Identity
#sqrt(a*b) = sqrta*sqrtb#
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- Squaring
#4*b^2# will give us#16*b^4# . And squaring#-(4*b^2)# will also give us#16*b^4#
Hence
