How do you simplify #sqrt(196)#?
It is a perfect squared, but there is a way to find it without knowing that.
First lets find the factors with a factor tree.
196 / \ 2 98 / \ 2 49 / \ 7 7
How many pairs of numbers do we have?
There is two; 2 and 7
Now take 2 times 7
So, the simplify of
using the following facts about radicals :
# sqrt(ab) =sqrta xx sqrtb hArr sqrta xx sqrtb = sqrt(ab) #
Find the factors of 196 looking for perfect squares.
these are 196 =
# 4 xx 49 #
Using the fact from above :
#sqrt196 = sqrt4 xx sqrt49 = 2 xx 7 = 14 #