How do you simplify #sqrt(2)/sqrt10#?

1 Answer
Feb 6, 2016

Answer:

#sqrt#5/5 (squareroot of five over five)

Explanation:

To remove the radical in the denominator, multiply both numerator and denominator by the value of the denominator.

= #sqrt#2/#sqrt#10 * #sqrt#10/#sqrt#10
= #sqrt#20 / #sqrt#100
= [#sqrt#4*5]/10
= [2#sqrt#5]/10
= 2/10 * #sqrt#5
= 1/5 * #sqrt#5
= #sqrt#5/5