How do you simplify # sqrt(27k^7q^8)#?
There are different ways to look at how to simplify root statements - I present one of mine below and get to
When we're dealing with simplifying a term within a root, I like to use the "buddy" rule - which is, in order for a term to "escape" the root, it needs the number of buddies listed in the root (a square root is 2 buddies, a cube root is 3 buddies, etc). When there is no number, like in this case, the default is 2.
Let's start with the original (but I'm going to add the 2 to indicate clearly this is a square root):
Now let's break down each part of the terms inside the root piece by piece:
Putting it all together, we get: