How do you simplify #sqrt(27x^4 )#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Bill K. Oct 5, 2015 Answer: #3sqrt(3)x^2# Explanation: First, note that #sqrt(27x^4)=sqrt(27)*sqrt(x^4)#. Next, since #27=9*3=3^2*3#, we can say #sqrt(27)=sqrt(9*3)=sqrt(9)*sqrt(3)=3*sqrt(3)#. Also, #sqrt(x^4)=sqrt((x^2)^2)=x^2# (in general, #sqrt(y^2)=|y|#, but if #y=x^2#, then #y\geq 0# anyway so we can get rid of the absolute value sign). Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 1089 views around the world You can reuse this answer Creative Commons License