How do you simplify #sqrt(28a^3b^2)#?

1 Answer
May 27, 2016

Answer:

#= 2ab sqrt(7a#

Explanation:

#sqrt(28a^3b^2#

Prime factorising #28# (expressing a number as a product of its prime factors):

#28 = color(green)( 2 * 2 * 7#

#= sqrt( color(green)(2 * 2 * 7) * a^3b^2#

#= sqrt( color(green)(2 ^2 * 7) * color(blue)(a^2) * a * color(blue)( b^2#

#= 2 * color(blue)(a * b) sqrt( color(green)( 7) * a#

#= 2ab sqrt(7a#