# How do you simplify sqrt(28x^3y^4)?

Apr 18, 2015

$\sqrt{28 {x}^{3} {y}^{4}}$

$= \sqrt{\left(7 \cdot 4\right) \left({x}^{2} \cdot x\right) {\left({y}^{2}\right)}^{2}}$

$= \sqrt{\left(7 \cdot {2}^{2}\right) \left({x}^{2} \cdot x\right) {\left({y}^{2}\right)}^{2}}$

color(green)( = 2*x*y^2sqrt(7x) is the Simplified Form of $\sqrt{28 {x}^{3} {y}^{4}}$

Sep 8, 2015

Simplifying the values can work out here.

#### Explanation:

the above can also be written as $\sqrt{28} {\sqrt{x}}^{3} {\sqrt{y}}^{4}$ for convenience.
1) $\sqrt{28}$=2$\sqrt{7}$
2) ${\sqrt{x}}^{3}$=x$\sqrt{x}$
3) ${\sqrt{y}}^{4}$= ${y}^{2}$
Hence on using 1,2 and 3 we get the answer=2x${y}^{2}$$\sqrt{7}$$\sqrt{x}$
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I hope this helps :)