How do you simplify #sqrt(3/(27y^6))#?

1 Answer
Sep 25, 2015

Answer:

#color(red)(sqrt(3/(27y^6))= 1/(3y^3))#

Explanation:

First divide the numerator and denominator by #3#.

#sqrt(3/(27y^6)) = sqrt(1/(9y^6))#

Remember that #sqrt(x^n) = x^(n/2)#

So #sqrt(y^6) = y^(6/2) = y^3# and

#sqrt(1/(9y^6)) = 1/(3y^3)#

#sqrt(3/(27y^6))= 1/(3y^3)#