# How do you simplify sqrt(40x^2y^3z^4)?

$\sqrt{40 {x}^{2} {y}^{3} {z}^{4}}$
$= \sqrt{\left({2}^{2} \cdot 10\right) \left({x}^{2}\right) \left({y}^{2} \cdot y\right) \left({\left({z}^{2}\right)}^{2}\right)}$
$= 2 x y {z}^{2} \sqrt{10 y}$