# How do you simplify sqrt(49x^12y^4z^8)?

Jul 16, 2018

$7 {x}^{6} {y}^{2} {z}^{4}$

#### Explanation:

$\sqrt{49 {x}^{12} {y}^{4} {z}^{8}} = \sqrt{{\left(7 {x}^{6} {y}^{2} {z}^{4}\right)}^{2}} = 7 {x}^{6} {y}^{2} {z}^{4}$

Jul 16, 2018

$\sqrt{49 {x}^{12} {y}^{4} {z}^{8}} = 7 {x}^{6} {y}^{2} {z}^{4}$

#### Explanation:

Find the square root of each factor.

Divide the indices by $2$

$\sqrt{49 {x}^{12} {y}^{4} {z}^{8}} = 7 {x}^{6} {y}^{2} {z}^{4}$

Only the principal (positive) root is required.