How do you simplify #sqrt(49x^12y^4z^8)#?

2 Answers
Jul 16, 2018

Answer:

#7x^6y^2z^4#

Explanation:

#sqrt(49x^12y^4z^8)=sqrt((7x^6y^2z^4)^2)=7x^6y^2z^4#

Jul 16, 2018

Answer:

#sqrt(49x^12y^4z^8) = 7x^6y^2z^4#

Explanation:

Find the square root of each factor.

Divide the indices by #2#

#sqrt(49x^12y^4z^8) = 7x^6y^2z^4#

Only the principal (positive) root is required.