How do you simplify #sqrt(4x^2 + 9x^4 + 16)#?

1 Answer
Jul 24, 2018

Answer:

#3x^2 + 2x + 4#

Explanation:

#sqrt(4x^2 + 9x^4 + 16)#

Using PEMDAS

Exponent

#(4x^2 + 9x^4 + 16)^(1/2)#

Reducing;

#(2^2x^2 + 3^2x^4 + 4^2)^(1/2)#

#(2^2x^2 + 3^2x^(2(2)) + 4^2)^(1/2)#

Multiplication

Multiplying via by the exponent;

#(2^(2 xx 1/2) x^(2 xx 1/2) + 3^(2 xx 1/2)x^(2(2 xx 1/2)) + 4^(2 xx 1/2))#

Simplifying;

#2^1 x^1 + 3^1x^(2(1)) + 4^(1)#

#2x + 3x^2 + 4#

Rearranging;

#3x^2 + 2x + 4 -> "Simplified"#