How do you simplify #sqrt(5/(32y^10))#?

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Answer 1 · 2018-04-05T16:54:18

#sqrt (10y^10)/(8y^10)#

#sqrt(5/(32y^10)#

#:.=sqrt(5)/sqrt(32y^10)#

#:.=sqrt(5)/sqrt(2*2*2*2*2y^10)#

#sqrt2*sqrt2=2#

#:.=sqrt 5/(4 sqrt (2 y^10))#

#:.=sqrt 5/(4 sqrt (2 y^10))xx(4 sqrt (2 y^10))/(4 sqrt (2 y^10))#

#sqrt (2 y^10)*sqrt (2 y^10)=2y^10#

#:.=(cancel4^1sqrt (10y^10))/(cancel16^4xx2y^10)#

#:.=(sqrt (10y^10))/(8y^10)#