How do you simplify #sqrt(64/81)#?

1 Answer
Jun 5, 2016

Answer:

#= 8/9#

Explanation:

For multiplication and division involving roots, you can find the roots separately.

So #sqrt(64/81) = sqrt64/sqrt81#

#= 8/9#

However for addition and subtraction you have to work with the terms as they are given

#sqrt(16 + 9) " is not the same as " sqrt16 +sqrt9#

#= sqrt25 " "= 4 + 3#

#= 5 " "= 7#