How do you simplify #sqrt(75)#?

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Answer 1 · 2018-05-20T11:06:48

#sqrt(75)=5sqrt(3)#

#sqrt(75)=sqrt(5^2 * 3) =sqrt(5^2) * sqrt(7)=5 * sqrt(7)#

Answer 2 · 2018-05-20T11:07:49

#5sqrt3#

We can simplify radicals using square numbers.

Start by listing the factors:

#75 and 1#
#25 and 3#
#15 and 5#

#25# is a squared number, so we can use #25# and #3#

#rArr sqrt25 xx sqrt3#

#sqrt25# can be simplified:

#sqrt25=5#

#therefore# #rArr 5sqrt3#