# How do you simplify sqrt((8z^2y^3))?

Oct 12, 2015

$2 y z \sqrt{2 y}$
$\sqrt{8 {z}^{2} {y}^{3}}$ =
$\sqrt{2.2 .2 \cdot {z}^{2} \cdot {y}^{2} \cdot y}$
$2. z . y \sqrt{2. y}$ or $2 y z \sqrt{2 y}$