How do you simplify #sqrt(9-(9/2))#?

1 Answer
May 4, 2016

Answer:

#(3sqrt(2))/2#

Explanation:

Consider the following: If you multiply a value by 1 you not change it value#" "6xx1=6#. However, 1 comes in many forms. One of them is #1=2/2" "# Multiplying by this does not change the value but it does change the way it looks.
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#color(blue)("Answering the question")#

Multiply the 9 by 1 but in the form of #1=2/2#

write as:#" "sqrt( (9xx2/2)-9/2)#

#sqrt(18/2-9/2)" "=" "sqrt(9/2)#

Write as: #" "sqrt(9)/sqrt(2)" "=" "3/sqrt(2)#

But it is not good practice to have a root as a denominator

Multiply by 1 but in the form of #1= sqrt(2)/sqrt(2)#

Giving:#" "3/sqrt(2)xxsqrt(2)/sqrt(2)#

#=(3sqrt(2))/2#