How do you simplify #\sqrt { 98x ^ { 4} y ^ { 6} z ^ { 23} }#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Nicola v. · Stefan V. May 10, 2017 Answer: #7x^2y^3z^11sqrt(2z)# Explanation: Factor the inside of the radical to #2*7*7*x^2*x^2*y^3*y^3*z^11*z^11*z# then for each pair of terms, move them outside the radical to get #7*x^2*y^3*z^11# which leaves unmatched #2# and #z# inside the radical. Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 205 views around the world You can reuse this answer Creative Commons License