# How do you simplify sqrt(9k^4)?

$\sqrt{9 {k}^{4}} = 3 {k}^{2}$

#### Explanation:

The given is a radical expression

$\sqrt{9 {k}^{4}}$

$\sqrt{{3}^{2} \cdot {\left({k}^{2}\right)}^{2}}$

$\sqrt{{3}^{2}} \cdot \sqrt{{\left({k}^{2}\right)}^{2}}$

$= 3 {k}^{2}$

God bless....I hope the explanation is useful.

Jul 9, 2016

$3 {k}^{2}$

#### Explanation:

$\sqrt{{a}^{b}} = {\left({a}^{b}\right)}^{\frac{1}{2}} = {a}^{b \cdot \frac{1}{2}}$

The square root of $9$ is $3$.

$\sqrt{9 {k}^{4}}$

$3 \sqrt{{k}^{4}}$

Using the concept from above:

$\sqrt{{k}^{4}} = {\left({k}^{4}\right)}^{\frac{1}{2}} = {k}^{4 \cdot \frac{1}{2}} = {k}^{\frac{4}{2}} = {k}^{2}$

So:

$3 {k}^{2}$