How do you simplify #sqrt(a^2/b^2)#?

1 Answer
Jul 13, 2015

Answer:

Use the rule #sqrt(x/y)=sqrtx/sqrty#

Explanation:

#=sqrta^2/sqrtb^2=|a|/|b|#

Since #a^2/b^2# is necessarily positive, we must assure that #a/b# is non-negative as well (that's why the absolute bars).

Or you could have used #x^2/y^2=(x/y)^2#

#=sqrt((a/b))^2=|a/b|#