How do you simplify #sqrt(h^11)#?

2 Answers
May 16, 2016

Answer:

#sqrt(h^11) = color(blue)(h^5sqrt(h))#

Explanation:

#sqrt(h^11)=sqrt(h^10*h)#

#color(white)("XXX")= sqrt((h^5)^2*h)#

#color(white)("XXX") =sqrt((h^5)^2)*sqrt(h)#

#color(white)("XXX")=h^5sqrt(h)#

May 16, 2016

Answer:

#h^5sqrt(h)#

Explanation:

The 'long way round' method to fully explain what is happening.

#sqrt(h^(11)) = sqrt(h^2xxh^2xxh^2xxh^2xxh^2xxh)#

There are 5 lots of #xxh^2# so by taking the square root of them we have 5 lots of #xxh# giving #h^5#

#h^5sqrt(h)#