How do you simplify sqrt(n^2-8) = sqrt(2-3n)?

1 Answer
Apr 16, 2016

n={-5,2}

Explanation:

sqrt(n^2-8)=sqrt(2-3n)

(sqrt(n^2-8))^2=(sqrt(2-3n))^2

n^2-8=2-3n

n^2-8-2+3n=0

n^2+3n-10=0

(n+5)(n-2)=0

if (n+5)=0" then " n=-5

if(n-2)=0" then " n=2

n={-5,2}