How do you simplify #sqrt140#? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Alan P. Apr 29, 2016 #sqrt(140)=2sqrt(35)# Explanation: #sqrt(140) = sqrt(2xx2xx5xx7)# #color(white)("XXX")=sqrt(2^2xx5xx7)# #color(white)("XXX")=sqrt(2^2)*sqrt(5xx7)# #color(white)("XXX")=2sqrt(35)# Answer link Related questions How do you simplify #(2sqrt2 + 2sqrt24) * sqrt3#? How do you simplify #sqrt735/sqrt5#? How do you rationalize the denominator and simplify #1/sqrt11#? How do you multiply #sqrt[27b] * sqrt[3b^2L]#? How do you simplify #7sqrt3 + 8sqrt3 - 2sqrt2#? How do you simplify #sqrt468 #? How do you simplify #sqrt(48x^3) / sqrt(3xy^2)#? How do you simplify # sqrt ((4a^3 )/( 27b^3))#? How do you simplify #sqrt216#? How do you simplify #sqrt540#? See all questions in Square Root Impact of this question 3734 views around the world You can reuse this answer Creative Commons License