How do you rationalize the denominator and simplify #1/sqrt11#? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Shwetank Mauria Jun 27, 2016 #1/sqrt11=sqrt11/11=0.3015# Explanation: To rationalize #1/sqrt11#, one should multiply numerator and denominator by #sqrt11#. Hence, #1/sqrt11=(1xxsqrt11)/(sqrt11xxsqrt11)# = #sqrt11/sqrt(11xx11)# = #sqrt11/11# = #3.3166248/11=0.3015# Answer link Related questions How do you simplify #(2sqrt2 + 2sqrt24) * sqrt3#? How do you simplify #sqrt735/sqrt5#? How do you multiply #sqrt[27b] * sqrt[3b^2L]#? How do you simplify #7sqrt3 + 8sqrt3 - 2sqrt2#? How do you simplify #sqrt468 #? How do you simplify #sqrt(48x^3) / sqrt(3xy^2)#? How do you simplify # sqrt ((4a^3 )/( 27b^3))#? How do you simplify #sqrt140#? How do you simplify #sqrt216#? How do you simplify #sqrt540#? See all questions in Square Root Impact of this question 12078 views around the world You can reuse this answer Creative Commons License