How do you simplify # sqrt3^2#?

2 Answers
Feb 3, 2016

Answer:

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
#sqrt(3^2)# it's one of the two numbers #+-a# such that #(+-a)^2=3^2=9#, so they are #sqrt(3^2)= +-3#
On the other hand, if we consider #(sqrt(3))^2#, you gotta take both #+-sqrt(3)# and take the square. But, by definition, #+-sqrt(3)# are the only two numbers such that #(+-sqrt(3))^2=3#, so the answer is #3#

Feb 3, 2016

Answer:

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
#sqrt(3^2)# it's one of the two numbers #+-a# such that #(+-a)^2=3^2=9#, so they are #sqrt(3^2)= +-3#
On the other hand, if we consider #(sqrt(3))^2#, you gotta take both #+-sqrt(3)# and take the square. But, by definition, #+-sqrt(3)# are the only two numbers such that #(+-sqrt(3))^2=3#, so the answer is #3#