How do you simplify square root of T to the 17th power?

$= {T}^{8} \sqrt{T}$
$\sqrt{{T}^{17}} = \sqrt{{T}^{16}} \times \sqrt{T} = {T}^{8} \sqrt{T}$
${\left(\sqrt{T}\right)}^{17} = {\left(\sqrt{T}\right)}^{16} \times \sqrt{T} = {T}^{8} \sqrt{T}$