How do you simplify #(t^2-4t-32)/(t-8)?#?

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Answer 1 · 2018-05-11T01:38:13

#t+4#

Let's factor the numerator. What two numbers have a sum of #-4# and a product of #-32#?

After some trial and error, we arrive at #-8# and #4#. Thus, we have

#((t-8)(t+4))/(t-8)#

which can be simplified to

#(cancel((t-8))(t+4))/cancel(t-8)#

#=>t+4#

Hope this helps!