How do you simplify $(t^2-4t-32)/(t-8)?$ ?

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Answer 1 · 2018-05-11T01:38:13

$t+4$

Let's factor the numerator. What two numbers have a sum of $-4$ and a product of $-32$ ?

After some trial and error, we arrive at $-8$ and $4$ . Thus, we have

$((t-8)(t+4))/(t-8)$

which can be simplified to

$(cancel((t-8))(t+4))/cancel(t-8)$

$=>t+4$

Hope this helps!

How do you simplify (t^2-4t-32)/(t-8)?(t^2-4t-32)/(t-8)??