How do you simplify #(t^2-4t-32)/(t-8)?#?

1 Answer
May 11, 2018

Answer:

#t+4#

Explanation:

Let's factor the numerator. What two numbers have a sum of #-4# and a product of #-32#?

After some trial and error, we arrive at #-8# and #4#. Thus, we have

#((t-8)(t+4))/(t-8)#

which can be simplified to

#(cancel((t-8))(t+4))/cancel(t-8)#

#=>t+4#

Hope this helps!