How do you simplify #(t^2-5t-6)/(t^2-7t+6)#?

1 Answer
Mar 26, 2018

Answer:

#(t+1)/(t-6)#

Explanation:

You have to factorize the top and bottom look for a factor that multiples into -6 and adds into -5

The possible factors are 6,1 and 3,2. We know that -6 and +1 add to -5 and multiply -6. Likewise the factors -6 and -1 add to -7 and multiply to 6.

#((t-6)(t+1))/((t-6)(t-1)#

can remove the common factor of #(t-6)# from denominator and numerator to get

#(t+1)/(t-6)#