Question

How do you simplify `tan (5π/2 + a)`?

Answer 1

`tan(5pi/2+a)=-cota`

Explanation:

`tan(5pi/2+a)`

= `tan(4pi/2+pi/2+a)=tan(2pi+pi/2+a)`

= `tan(pi/2+a)`

If `a` is in first quadrant, `(pi/2+a)` will be in second quadrant and hence

`tan(pi/2+a)=-cota`