How do you simplify the expression #sqrt(-64x^4)#?

1 Answer
Tony B
Apr 15, 2016

#=>8x^2 i#

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Explanation:

As soon as you see a negative value to have its square root calculated you know that complex numbers are involves.

Write as # sqrt( (-1)xx8^2xx x^2xx x^2)#

#=>8xx x xx x xx sqrt(-1)" " =" " 8x^2sqrt(-1)#

But #sqrt(-1) = i#

#=>8x^2 i#

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