# How do you simplify the product (3x - 1)(2x + 1)  and write it in standard form?

Dec 31, 2015

Use FOIL method and get the following solution $6 {x}^{2} + x - 1$

#### Explanation:

Use FOIL Method

F- First
O- Outer
I - Inner
L - Last

$\left(3 x - 1\right) \left(2 x + 1\right)$

First terms $\left(3 x\right) \left(2 x\right) = 6 {x}^{2}$
Outer terms $\left(3 x\right) \left(+ 1\right) = 3 x$
Inner terms $\left(- 1\right) \left(2 x\right) = - 2 x$
Last terms $\left(- 1\right) \left(+ 1\right) = - 1$
$6 {x}^{2} + 3 x - 2 x - 1$
$\left(6 {x}^{2} + x - 1\right)$
$\left(3 x - 1\right) \left(2 x + 1\right) = 6 {x}^{2} + x - 1$ answer