How do you simplify the radical expression #sqrt(32x^5)#?

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Answer 1 · 2017-04-20T09:05:29

#4x^2sqrt(2x)#

Write down your equation as
#sqrt((16x^4)(2x)#

Now take the first term out:
#4x^2sqrt(2x)#

This is the simple form of your equation
#4x^2sqrt(2x)#

Answer 2 · 2017-04-20T10:47:21

#color(green)(4x^2sqrt(2x)#

#sqrt(32x^5)#

#:.sqrt(4*4*2*x*x*x*x*x#

#:.sqrt4*sqrt4=4#

#:.sqrtx*sqrtx=x#

#:.4*x*x*sqrt(2*x)#

#:.color(green)(4x^2sqrt(2x)#