# How do you simplify this?

## $\frac{\sqrt{48} {n}^{6}}{\sqrt{6} {n}^{3}}$

For $\frac{\sqrt{48} \times {n}^{6}}{\sqrt{6} \times {n}^{3}}$?
$\frac{\sqrt{48} \times {n}^{6}}{\sqrt{6} \times {n}^{3}} = \frac{\cancel{\sqrt{6}} \times \sqrt{8} \times {n}^{3} \times \cancel{{n}^{3}}}{\cancel{\sqrt{6}} \times \cancel{{n}^{3}}}$
$=$ ${n}^{3} \sqrt{8} = 2 \sqrt{2} {n}^{3}$