How do you simplify this?

Question

#(sqrt48n^6)/(sqrt6n^3)#

741 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-15T19:06:38

For #(sqrt(48)xxn^6)/(sqrt6xxn^3)#?

#(sqrt(48)xxn^6)/(sqrt6xxn^3)=(cancelsqrt6xxsqrt8xxn^3xxcancel(n^3))/(cancelsqrt6xxcancel(n^3))#

#=# #n^3sqrt8=2sqrt2n^3#