Question

How do you simplify `(w^3-27)/(4w^2-5w-21)`?

Answer 1

Factorizing the fraction we get

`(w^3-27)/(4w^2-5w-21)`

`((w - 3) (w^2 + 3 w + 9))/((w - 3) (4 w + 7))`

`((cancel(w - 3) )(w^2 + 3 w + 9))/((cancel(w - 3)) (4 w + 7))`

`(w^2 + 3 w + 9)/(4 w + 7)`