# How do you simplify (w^3-27)/(4w^2-5w-21)?

$\frac{{w}^{3} - 27}{4 {w}^{2} - 5 w - 21}$
$\frac{\left(w - 3\right) \left({w}^{2} + 3 w + 9\right)}{\left(w - 3\right) \left(4 w + 7\right)}$
$\frac{\left(\cancel{w - 3}\right) \left({w}^{2} + 3 w + 9\right)}{\left(\cancel{w - 3}\right) \left(4 w + 7\right)}$
$\frac{{w}^{2} + 3 w + 9}{4 w + 7}$