How do you simplify $\frac{- w - 6}{w^{2} + 4 w - 12}$ $(-w-6)/(w^2+4w-12)$ ?

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Answer 1 · 2016-06-27T02:47:29

$\frac{- 1}{w - 2}$ $(-1)/(w-2)$

Step 1: Factorize the quadratic equation.

$w^{2} + 4 w - 12$ $w^2+4w-12$ can be written as $w^{2} + 6 w - 2 w - 12$ $w^2+6w-2w-12$

=> $w (w + 6) - 2 (w + 6)$ $w(w+6) -2(w+6)$ = $(w + 6) (w - 2)$ $(w+6)(w-2)$

Step 2: Now substitute the factors in the denominator of the given problem as

$\frac{- 1 \cdot (w + 6)}{(w + 6) (w - 2)}$ $(-1*(w+6))/((w+6)(w-2))$

Cancelling $(w + 6)$ $(w+6)$ , we get $\frac{- 1}{w - 2}$ $(-1)/(w-2)$

How do you simplify (-w-6)/(w^2+4w-12)−w−6w2+4w−12(-w-6)/(w^2+4w-12)?