How do you simplify #(-w-6)/(w^2+4w-12)#?

1 Answer
jags
Jun 27, 2016

#(-1)/(w-2)#

Explanation:

Step 1: Factorize the quadratic equation.

#w^2+4w-12# can be written as #w^2+6w-2w-12#

=> #w(w+6) -2(w+6)# =# (w+6)(w-2)#

Step 2: Now substitute the factors in the denominator of the given problem as

#(-1*(w+6))/((w+6)(w-2))#

Cancelling #(w+6)#, we get #(-1)/(w-2)#

Related questions
See all questions in Division of Polynomials
Impact of this question
1657 views around the world
You can reuse this answer
Creative Commons License