# How do you simplify (x -1)(x^2+ 5x-2)?

Oct 24, 2016

${x}^{3} + 4 {x}^{2} - 7 x + 2$

#### Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.
This can be achieved as follows.

$\left(\textcolor{red}{x - 1}\right) \left(\textcolor{b l u e}{{x}^{2} + 5 x - 2}\right)$

$= \textcolor{red}{x} \left(\textcolor{b l u e}{{x}^{2} + 5 x - 2}\right) \textcolor{red}{- 1} \left(\textcolor{b l u e}{{x}^{2} + 5 x - 2}\right)$

distribute the brackets.

$= {x}^{3} + 5 {x}^{2} - 2 x - {x}^{2} - 5 x + 2$

collect like terms.

${x}^{3} + \left(5 {x}^{2} - {x}^{2}\right) + \left(- 2 x - 5 x\right) + 2$

$= {x}^{3} + 4 {x}^{2} - 7 x + 2$