# How do you simplify [(x^-3y^-5z)^4]^3/(x^6y^10z^2)^-6?

Dec 3, 2016

${y}^{120} {z}^{24}$

#### Explanation:

[(x^-3y^-5z)^4]^3/ (x^6y^10z^2)^-6

Most of solving this equation involves the rule:

${\left({x}^{a}\right)}^{b} = {x}^{a b}$

for example:

=(x^-3y^-5z)^12/ (x^6y^10z^2)^-6

and goes on to give us:

$\frac{{x}^{-} 36 {y}^{60} {z}^{12}}{{x}^{-} 36 {y}^{-} 60 {z}^{-} 12}$

the other rule is:

${x}^{a} / {x}^{b} = {x}^{a - b}$

and this gives us:

${x}^{0} {y}^{120} {z}^{24}$

or more simply, ${y}^{120} {z}^{24}$ since ${x}^{0}$=1