How do you simplify $\frac{x - 5}{x^{2} - 25}$ $(x-5)/(x^2-25)$ ?

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Answer 1 · 2016-08-05T21:53:22

$= \frac{1}{x + 5}$ $= 1/(x+5)$

Factorise the denominator as the difference of squares.

$\frac{(x - 5)}{(x + 5) (x - 5)}$ $((x-5))/((x+5)(x-5))$

$(cancel(x-5))/((x+5)cancel(x-5))$

$= 1/(x+5)$

How do you simplify (x-5)/(x^2-25)x−5x2−25(x-5)/(x^2-25)?