How do you simplify #x^6/ x^2#?

2 Answers
Apr 14, 2017

Answer:

#x^4#

Explanation:

Let's write the equation in this form #(x^4*x^2)/(x^2)#

Now numerator's #(x^2)# will cancel the one in the denominator:
#(x^4\cdot\cancel(x^2))/(\cancel(x^2))=x^4#

Yielding #x^4#.

Apr 14, 2017

Answer:

(the previous answer also works)!
#x^4#

Explanation:

#x^a/x^b=x^(a-b)#

here you have #a=6# and #b=2#
#\thereforex^6/x^2\rArrx^(6-2)=x^4#