How do you simplify #x/(x^2+1)divx/(x^4-1)# and state the domain? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Noah G Nov 11, 2016 #y = x/(x^2 + 1) xx (x^4 - 1)/x# #y= x/(x^2 + 1) xx ((x^2 + 1)(x^2 - 1))/x# #y = x^2 - 1# The domain will be #{x|x in RR, x!=+-1, 0}# Hopefully this helps! Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 2139 views around the world You can reuse this answer Creative Commons License