How do you simplify #(y^2+8y-9)/(y^2-5y+4)#?

1 Answer
EZ as pi
Jul 23, 2016

=#((y+9))/((y-4))#

Explanation:

Although we have a fraction, we MAY NOT CANCEL, because there are + and - signs in the numerator and denominator indicating that there are terms, rather than factors.

Factor the numerator and denominator first.

#((y+9)(y-1))/((y-4)(y-1)) " now we have factors"#

#((y+9)cancel(y-1))/((y-4)cancel(y-1))#

=#((y+9))/((y-4))#

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