# How do you sketch the angle whose terminal side in standard position passes through (-8,-6) and how do you find sin and cos?

Feb 28, 2017

$\sin t = - \frac{3}{5}$
$\cos t = - \frac{4}{5}$

#### Explanation:

Call t the angle whose terminal side passes through point M (-8, -6):
t is located in Quadrant 3.
The hypotenuse $O M = \sqrt{{6}^{2} + {8}^{2}} = \sqrt{100} = 10$
$\sin t = - \frac{6}{10} = - \frac{3}{5}$
$\cos t = - \frac{8}{10} = - \frac{4}{5}$