# How do you sketch the general shape of #f(x)=-x^4+3x^2-2-5x# using end behavior?

##### 1 Answer

Dec 2, 2016

#### Answer:

As

There are two points of inflexion at

#### Explanation:

f(x) has alternate signs at x = 0, -1 and -2. So, the graph cuts xaxis

twice in (-2, -1).

f'=-4x^3+6x-5 and changes sign nera x = -1.5, for a turning point.

So, the points of inflexion are

graph{-x^4+3x^2-5x-2 [-20, 20, -10, 10]}