# How do you sketch the general shape of #f(x)=-x^4+3x^2-2x-4# using end behavior?

##### 1 Answer

Dec 5, 2016

y-intercept ( x = 0 ) : -4. Cuts x-axis at x = -1 and again between x = -2

and x = -1. As

#### Explanation:

Sign changing of a functions y and y'', in an interval, reveals the

presence of zero(s) of the function, within the interval.

So, the points of inflexion ( tangent crossing curve ) are at

graph{y+x^4-3x^2+2x+4=0 [-20.18, 20.18, -10.1, 10.07]}

=