# How do you sketch the general shape of #f(x)=x^5-3x^3+2x+4# using end behavior?

##### 1 Answer

Jan 21, 2017

See graph and explanation. The second graph reveals turning points and points of inflexion (POI).

#### Explanation:

graph{x^5-3x^3+2x^2+4 [-39.86, 39.8, -20.43, 19.43]}

zeros x = +-1.24 and +-0.51, nearly,

So, the POI are at

The second graph locates the turning points and POE that could not

be located in the first graph

.graph{x^5-3x^3+2x^2+4[-1.5, 1.5, -20.43, 19.43]}