How do you sketch the graph of #y=1/2x^2# and describe the transformation?

1 Answer
Jul 25, 2018

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Please read the explanation.

Explanation:

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We have the quadratic equation: #color(red)(y=f(x)=(1/2)*x^2#

Consider the Parent Function: #color(blue)(y=f(x)=x^2#

The General Form of a quadratic equation is:

#color(green)(y=f(x)=a*(x-h)^2+k#, where #color(red)((h,k) # is the Vertex

The graph of #color(blue)(y=f(x)=x^2#

pass through the origin #color(blue)((0,0)#

and the graphs uses both Quadrant-I and Quadrant-II.

Let us now look at the transformation of the graph.

Consider the format : #color(blue)(y=f(x)=a*x^2#

#color(red)([0 < | a | < 1]# results in a compression.

Since, in the problem,

#color(red)(y=f(x)=(1/2)*x^2#,

#color(green)(a=(1/2)#,

there will be a vertical compression toward the x-axis.

The graph is below:

Note that the graphs of

#y=f(x)=x^2# and

#y=f(x)=(1/2)*x^2#

are available together to examine the transformation.

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