# How do you sketch the graph of y=-1/4x^2 and describe the transformation?

Dec 11, 2017

This is an equation of parabola.
Standard equation of a parabola with Y axis symmetry is given by
${\left(X - h\right)}^{2} = 4 p \left(Y - k\right)$

#### Explanation:

Simply rearranging the terms from y= $- \frac{1}{4} {x}^{2}$
you can get the standard equation of a parabola
as $4 \cdot \left(- 1\right) \left(Y - k\right) = {\left(x - 0\right)}^{2}$.
This is a downward opening parabola with negative Y axis as the axis of symmetry.
From the standard equation the co-ordinates of focus are (h,k+p).
So the focus of this parabola is (0,-1).
the vertex is (h,k) => vertex is (0,0)