I like getting rid of the phase shift (the #x + pi# part) using the sum and difference formulas. The one that is applicable here is
#cos(A + B) = cosAcosB - sinAsinB#.
We have:
#y = 3(cosxcos(pi) - sinxsinpi) - 3#
#y = 3(cosx(-1) - 0) - 3#
#y = -3cosx - 3#
Now you need a little bit of knowledge on the basic cosine function, #y = cosx#. Here's the graph:
graph{y = cosx [-10, 10, -5, 5]}
Whenever there is a coefficient #a# next to the cosine, you have an altered amplitude, which is the distance between the centre (the line #y = 0#) and the top or bottom of the curve.
In the graph of #y = cosx#, the amplitude is simply #1#. In the graph of #y = -3cosx - 3#, the amplitude will be #3#.
The #-# is in front of the #3# to signify a reflection over the x-axis.
Finally, the #-3# to the far right of the equation signifies a vertical transformation of #3# units down. We are left with the following graph:
graph{y = -3cosx - 3 [-10, 10, -5, 5]}
Hopefully this helps!